Proof.
Let be a matrix and
be the column vectors of .
Then
. This means that multiplying a vector with a matrix is linear
combination of the columns, the coefficient is the component of . Since
is a boolean and acts as an indicator variable on the selection of column . So if
is chosen from a uniform distribution
.
Now let and be the column vectors of , similarly let be the column vectors of . Let , clearly since . Then since . Intuitively this means we select our random vector such that for all , such a selection will always ensure even though .
Proof.
Continuing with the proof of Theorem- 1 ,
.
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